# Building a pattern of the base is the most understandable way for an ideal fit.

We represent you the construction of a pattern of the basis - the most understandable way. Let's start with the base of the dress, blouse or jacket - that is, the shoulder product.

We take measurements (we have given an example of individual measures for 48 sizes of an untypical figure), cm:

• SG-49;
• ST - 41;
• SB-55;
• ШС - 21;
• СШ - 17;
• ShG1 - 21;
• ShG2 - 25;
• VG - 28;
• WB - 19;
• ЦГ - 10;
• Accident - 43;
• DTS - 40;
• MIC - 42;
• VGK (from the nipple to the shoulder) - 25;
• ШП - 14;
• ШПсп (shoulder width on the back from the cervical vertebra) - 23;
• ШПп (shoulder width along the front from the jugular hollow) - 20;
• CI (from the waist) transfers 48 (better than 50);
• OP - 31;
• ДР - 60;
• OZ - 21;
• ДР 3 \ 4 - 45.

### Begin to build a pattern of the base - the most understandable way

AA6 up is equal to SG2 + PG

ATvniz = accident. TN down - CI. TB down = WB. Аввниз = ВГР

AA11 right and Y2 right = W2

T10A10 = DTc2

A10A12 to the left = Г6Г4 = ШС + ПШС =

AA1 to the right = CI \ 3 + Rx =

Шпп -Шсп = 1,5

If the difference Rmn and Rdn is greater than 1 cm, then A10A8 to the left is equal to CU / 3 + Pr = AA1 + difference Rnn and Rdn. If the difference between Shmn and Shchp is more to the side, then in this case AA1 = A10A8 + is the difference.

AA2 = 8 const (from 6 to 10)

A2A1 - connect with a smooth concave line.

When decorating the neck and sprout, the line should start at a right angle.

A10A9 down 3 cm const

A8A9 - connect with a smooth concave line

A1A4 to the right is equal to the radius = WR.
ГГ1 to the right = ЦГ (1 \ 2 from the initial)

Г1А4 radius = ВГК before crossing with ГГ1.

At the intersection of the line T1 with A4, we obtain the point A3.

A3A5 - tumbling solution = (ШГ2 -ШГ1) * 2 =

A3A5 - the first radius = the tuck solution

G1A3 - equal to the second radius - postpone

A5A6 is equal to A3A4 (retired part of the shoulder)

G1A6 = HVG

T10T11 to the left - 2.5 cm

1) А8А7 = ШП

2) T11A11 = MIC

Г2Г4: 2 = Г3

ГГ3 = ТТ5 = ББ5 = НН1

T5G9 above - the height of the barrel

We find the lower part of the armhole.

G9G8 down - max up to 5 cm (otherwise, if we sweep the sleeve, we can not raise the hand, the dress will climb up behind the sleeve).

We output the armhole with a smooth curved line through the points A6, T8 and A7T8.

### Building a pattern of the base - the most understandable way - landing on a figure

Calculation of thallium darts

СГ2 + Пг - (СТ + Пт) =

Left T10T11 - minus 2.5 cm

T11 T9 to the left = at least 6 cm

T9T8 to the left equals 3 cm. Divide in half, we obtain the point T7. Draw perpendicular up and down.

B6B7 up - 3 cm const

A8G10 is divided by 3, we obtain Г5

The connection of G5T8B7 and G5T9B7

B9B8 to the left 1 cm

We connect A9T7 by a smooth convex line dividing the distance by 3

T5T4 to the left = remainder FROM

We measure BB8 and compare it with SB. CONTROL!

If the difference between them in the direction of the hips, then we can narrow the hips, and the dress will not stretch

If you need to add on the thigh then from the B5 we extend the hips to the desired number of centimeters

1) Г1Т1

2) T1T3 to the right 1 cm

3) BB2 to the right from 5 to 7 cm

### Building a pattern of the base is the most understandable way - asingle-hose sleeve

OP down - measure the distance, connecting A12A14. Join and divide by 2. The point A15 turns out

Lower the perpendicular down to the bottom line of the armhole near the point G6. We get the point Γ10. We measure the distance A15G10

Formula A15G10 - (2.5 - up to 3 cm)

OR down = A15G10 -3

PP1 = OO1

O2 = OO1: 2

OP = OP: 2

O1n1 = O1P1: 2

PP2 down = ", 5 cm const

PP3 up = 2.5 cm const

Expand the width of the sleeve

PP3 to the left = PP2

P1P4 to the right = P2P1

O2O3 upwards = OO2

O3O4 to the left is 1 cm const

O3O5 to the right = 1cm const

We connect O4n2 and on the line the width of the sleeve point P5

We connect O4P2P5 and O5N3P6. We design the line of the pellet of the sleeve through the points O2P2P3 smoothly. O2P34

Н1Н2 to the right - 12,5 sm (ШНР: 2)

Н1Н3 to the left - 12,5

We connect P3H2 P4H3.

Your attention is represented by a step-by-step construction of the pattern of the base of the dress. If even at first glance everything looks frightening, it's worth trying, and you will succeed.

Having studied this point of pattern building, you can proceed to the next step - to master the construction of the pattern of the base of the trousers.